In a circle of diameter 42cm,if an arc subtends an angle of 60˚ at the centre
where ∏=22/7, then what will be the length of arc.
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r = 21 cm.
theta = 60°
pii = 22/7.
ans :-
as we know that
L = r × theta
where theta should be in radian.
therefore L= r× theta
L = 21 × 60 × pii/ 180
L = 21/3 × pii
L = 21/3 × 22/7
L = 22 cm
therefore thought of arc is 22 cm
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