Question

In a circle of diameter 42cm ,if an arc subtends an angle of 60 ˚ at the centre where∏=22/7,then the length of the arc is ?

Answer 1

Answer:

Given:-

dimeter = 42cm

angle (θ) = 60 degree

π = 22/7

To find :-

length of an arc:- ?

Solution:-

As we know that

$\sf⇒ l = r \times \theta \: l=r \times θ$

(where θ should be in radian.)

so, by putting all given value in thise above example:

We get,

$\sf \: ⇒ l = 21 \times 60 \times \frac{\pi}{180}\: \\ \\ \sf \: ⇒ l = 21 \times \frac{\pi}{3}$

$\sf⇒ l = \frac{21}{3} \times \frac{22}{7} ---- \bigg( as \: it \: is \: given \: that \: \pi = \frac{22}{7} \bigg) \\ \\ \sf \: ⇒ l = \bold{22\: cm} \:$

therefore :-

length of an arc is 22 cm...