In a circle of diameter 60cm, the length of the chord is 30cm. find the length of minor arc of the chord.
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radius=diameter/2=30=chord
Two radius and chords form an equilateral triangle
the length of minor arc of the chord:
60*3.14/6=31.4cm
Two radius and chords form an equilateral triangle
the length of minor arc of the chord:
60*3.14/6=31.4cm
Answered by
1
Answer:
= 31.4 cm
Step-by-step explanation:
Given that ,
A circle of dimeter = 60 cm
Length of the chord = 30 cm
To find the length of minor arc?
So,
Length of radius of circle = D/2
= 60/2
= 30 cm
And the length of chord = 30 cm
here , if we join radius and chord then it form a
equialateral triangle and the angle subtended
to minor arc of chord Ф= π/3
So, by using the formula.
Ф = l/r { where, Ф = angle, l = arc length , r = radius }
l = Фr
l = π/3 × 30
l = 10π
l = 10 × 3.14
l = 31.4 cm
Therefore, the length of minor arc of the chord = 31.4 cm
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