Question

In a circle of diameter 66 cm, the length of a
chord is 33 cm. The length of minor arc of the
chord is
(A) 337 cm
(B) 117 cm
(C) 227 cm
(D) 5.510 cm​

Answer 1

Answer:

227 the answer of this question

Answer 2

Answer:

$\huge\underline\mathfrak\red{Answer}$

= give diameter = 40cm

∴ find radius

∴using formula:-

$= = > radius = \frac{d}{2}$

$= = >radius = \frac{66}{2}$

$= = > radius = 33$

in figure:-

∴AB=r = 33cm

∴AC= r = 33cm

∴BC= length of the chord = 33cm

∴so, AB=AC=BC= 33cm

∴hence, ∆ ABC is equilateral.

∴as in equilateral triangle all angles are 60°

hence ∠BAC is 60°

∅=60

hence ∅ = 60°

radius measure π/180× degree measure.

= 60°× π/180

= π/3

now putting value in formula

= ∠=rø

= 33 × π/ 3

= 33π/3

= hence the minor arc of the chord is = 33π/3

= 11cm