In a circle of radius 10.5 cm minor arc is 1/5th of major arc . Find area of sector corresponding to major arc
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minor arc=1/5 of major arc
by applying ar of the arc for the minor arc
teta/360*2*22/7*10.5
since the minor arc is 5 times th majorthe angle is
360/5=72
substituting this in formulae
we get
13.2cm
now find circumfrence of the circle 2*pie*r
2*22/7*10.5=66cm
now since minor arc is 13.2 and cis 66
therefor major arc is 66-13.2=52.8
by applying ar of the arc for the minor arc
teta/360*2*22/7*10.5
since the minor arc is 5 times th majorthe angle is
360/5=72
substituting this in formulae
we get
13.2cm
now find circumfrence of the circle 2*pie*r
2*22/7*10.5=66cm
now since minor arc is 13.2 and cis 66
therefor major arc is 66-13.2=52.8
anmol6433:
hope it may help you
Answered by
3
Answer:- Area of sector corresponding to the major arc is 288.75 square cm.
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