Question

In a circle of radius 10 cm ,find the distance of a chord of length 12cm​

Answer 1

Step-by-step explanation:

Radius of the circle = 10 cm. Distance of the midpoint of the chord from the centre of the circle = [10^2–6^2]^0.5 = [100–36]=√64=8cm

Answer 2

A line passing from the centre of circle to chord bisect the chord.

Angle OGB=90°

So let us draw a diagram as provided in the picture.

Now;

OB=OC=radius=10 cm

OG=Distance from centre of circle to chord

FB=1/2 x GB=1/2 x 12=6 cm

In ΔAGB;

By pythagoreas theorem we get;

Hypoteneuse²=Base²+Height²

OB²=GB²+OG²

(10)²=(6)²+OG²

OG²=100-36

OG²=64

OG=√64

OG=8 cm

Therefore Distance from centre of circle to chord=8 cm.

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