In a circle of radius 10 cm, two chords AB and CD are equal . Chord AB is at a distance of 6 cm from the centre O , what is a distance of chord CD from center O ?
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Answer:
6 CM because equal chords are equidistant from the centre of the circle
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Answer:
Since equal chords are equidistance from centre.
So distance of CD = 6 cm
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