In a circle of radius 12 cm, a chord subtends an angle of 120° at the centre. Find the
area of the corresponding minor segment of the circle (use π =3.14 and 13 = 1.732)
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Expert Answer:
Draw OM AB in figure
(RHS congruence)
AOM=BOM
BOM = (cpct)
In OMA
cos 60o =
OM = 6 cm
and sin 60o =
AM = 6 cm
ar AOB = AB OM = AM OM = 36 cm2
area of segment AXB
= area of sector OAXB - ar AOB
= 3.14 12 12 - 36
= (150.72 - 36) cm2
= 88.36 cm2
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