in a circle of radius 13 cm a chord is drawn at a distance 12cm from the center find the the length of courd
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Let AB be a chord of circle with centre O and radius 13cm. Draw OM perpendicular AB and join OA.
In the right triangle OMA, we have
OA2 = OM2 + AM2
⇒ 132 = 122 + AM2
⇒ AM2 = 169 - 144 = 25 ⇒ AM = 5cm.
As the perpendicular from the centre of a chord bisects the chord.Therefore,
AB = 2AM = 2 x 5 = 10cm.
ANSWER:–
ANSWER:–10 cm
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