In a circle of radius 13cm, two parallel chords of length 24 cm and 10 cm are drawn. Find the distance between the chords if both the chords are on the opposite sides of the centre.
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Answer:
Perpendicular from centre bisects the chord ⇒AQ=12cm,BS=5cm
By pythagorus theorem,
OA=
OA
2
−AQ
2
=
169−144
=5cm
OB=
OS
2
−BS
2
=
169−25
=12cm
⇒AB=17cm.
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