In a circle of radius 13cm, two parallel chords of lengths 10cm and 24cm are drawn on
the same side of the diameter. What would be the distance between the chords
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cm. B.
2 cm. C.
3 cm. D.
4 cm. MEDIUM. Answer. Let AB=8 cm is the chord of the circle with radius 5 cm. Draw OP⊥AB and join BO. PB=21AB=21×8=4cm. In △BPO∠P=90∘ ∴OB2=PB2+OP2. ⇒OP2=OB2−PB2. ⇒OP=52−42. ⇒OP=25−16 ⇒9 =3cm. Let CD=6 cm is the chord of the circle with radius 5 cm. Draw OQ⊥CD and join DO. QD=21CD=21×6=3cm. In △QDO∠Q=90∘
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