In a circle of radius 21 cm, an are subtends angle of 60° at the centre. Find the length of the arc.
Question Number. 6
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HELLO DEAR,
given that:-
radius of Circle = 21cm
and
∅ = 60°
length of arc of a sector of ∅
=> ∅/360 × 2πr
=> 60/360 × 2 × 22/7 × 21
=> 1/6 × 2 × 22 × 3
=> 1/6 × 6 × 22
=> 22cm
I HOPE ITS HELP YOU DEAR,
THANKS
given that:-
radius of Circle = 21cm
and
∅ = 60°
length of arc of a sector of ∅
=> ∅/360 × 2πr
=> 60/360 × 2 × 22/7 × 21
=> 1/6 × 2 × 22 × 3
=> 1/6 × 6 × 22
=> 22cm
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
:-)
Answered by
6
Hey mate !!!
radius is given => 21 cm
angle => 60°
now , area of sector => theta/ 360 ° *πr²
=> 60°/ 360° *22/7 *21 *21
so the area of sector we get
11 * 21 cm ²
=> 231cm².
now
we use this formula
area of sector => 1/2 * length of arc * radius
231 cm ² = 1/2 *21 length of arc
hence the length of arc comes out to be => 22 cm .
hope it helps :D
thanks
radius is given => 21 cm
angle => 60°
now , area of sector => theta/ 360 ° *πr²
=> 60°/ 360° *22/7 *21 *21
so the area of sector we get
11 * 21 cm ²
=> 231cm².
now
we use this formula
area of sector => 1/2 * length of arc * radius
231 cm ² = 1/2 *21 length of arc
hence the length of arc comes out to be => 22 cm .
hope it helps :D
thanks
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