in a circle of radius 25 cm , a chord is drawn at a distance of 7 cm from the centre , then the length of the chord will be?
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Answered by
1
Answer:
7 cm
Step-by-step explanation:
Answered by
113
Answer:
Given :-
➪ OD = 7cm
➪ OB = 25cm
Since, OD BC
➪ it bisects BC
➪ BD = DC
In ∆ OBD,
➪ BD² = OB² – OB² – 25² – 7²
➪ 625 – 49 = 576
➪ BD = √576 = 24
➪ chord BC = 2 × 24cm = 48cm
➪ 48cm
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