Question

In a circle of radius 25 cm, AB and AC are two chords, such that AB

= AC = 30 cm . Find the length of the chord​

Answer 1

Answer:

39.28 cm is the length of the chord.

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Answer 2

Answer:

AB and AC are two equal chord of a circle, therefore the centre of the circle lies on the bisector of ∠BAC. OA is the bisector of ∠BAC. Again, the internal bisector of an angle divides the opposite sides in the ratio of the sides containing the angle. P divides BC in the ratio 6:6=1:1.

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