Question

In a circle of radius 5 cm,AB and AC are two chords such that AB = AC = 6 cm.the perpendicular distance of A from BC is

Answer 1

Answer:

Since, the angular bisector of the angle between two equal chords of a circle passes through the centre therefore, AO and so AM is the bisector of ∠BAC and also is perpendicular bisector of chord BC. Hence, length of the chord BC = 2 BM = 2 × 4·8 = 9·6 cm. was