In a circle of radius 5 cm. AB and AC are two chords such that AB= AC = 6 cm find the length of the chord BC
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Answer:10 cm
Step-by-step explanation:
Create chord AB and AC of 6 cm
Mark the Center of the circle as O
Now, join BC
Observe the diagram and imply that BC passes through the Center of the circle
Since BO = CO = 5 cm
and BC = BO + CO
BC = 5 + 5
= 10 cm
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