In a circle of radius 5 cm, AB and CD are two parallel chords of lenghty 8 cm and 6 cm respectively. Calculate the distance between the chords, if they are on
i) The same size of the circle
ii) There opposite sides of the circle.
Answers
Answered by
1
Step-by-step explanation:
AB=8cm
⇒AE=4cm
CD=6m⇒CF=3cm
In△AED
AE=4cm,AO=5cm
OE=
(AO)
2
−(AE)
2
=
5
2
−4
2
=3cm
In△OFC
CF=3cm,CO=5cm
OF=
OC
2
−CF
2
=
5
2
−3
2
=4cm
∴ Distance between the chords=4cm−3cm=1cm
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Answered by
0
Ans (I) 1cm
Ans (II) 7cm
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