Question

In a circle of radius 5cm,AB and CD are two parallel chords of lenths 8cm and 6cm respectively.Calculate the distance between the chords if they are on the same side of the centre

Answer 1

⭕️In the figure above the perpendiculars bisect the chord.

➖or➖

⭕️AP=AB/2
=8/2
=4cm



⭕️CQ=CD/2
=6/2
=3cm



✔️✔️In Δ APO

Use Pythagoras theorem:-

AO²=AP²+PO²
5²=4²+PO²
=√25-16[whole root]
=√9
=3cm



✔️✔️In ΔCOR

Use Pythagoras theorem :-

OC²=CR²+RO²
5²=3²+RO²
RO=4cm

✔️✔️PR=OR-OP
=4-3
=1cm





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