In a circle of radius 5cm, angle between pair of tangents are twice of angle between the radii. Then angle between radii at the center is ___ ? A) 30 B) 60° C) 45° D) 90
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Option C
Given- O is the centre of a circle to which a pair of tangents PQ&PR from a point P touch the circle at Q&R respectively. ∠RPQ=60o.
To find out- ∠ROQ=?
Solution- ∠OQP=90o=∠ORP since the angle, between a tangent to a circle and the radius of the same circle passing through the point of contact, is 90o. ∴ By angle sum property of quadrilaterals, we get ∠OQP+∠RPQ+∠ORP+∠ROQ=360o⟹90o+60o+90o+∠ROQ=360o⟹∠ROQ=120o.
Ans- Option C.
hope it helped :)
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