Question

in a circle of radius 6cm an arc subtends an angle of 60° at the centre.find the area of sector​

Answer 1

Step-by-step explanation:

Given:-

In a circle of radius 6cm an arc subtends an angle of 60° at the centre.

To find:-

Find the area of sector?

Solution:-

Given that

Radius of a circle (r) = 6 cm

Angle subtends by an arc at the centre of the circle (X°)=60°

We know that

Area of a sector = (X°/360°)×πr^2 sq.units

We have

r = 6 cm and X°=60°

On Substituting these values in the above formula then

Area of the sector

=> (60°/360°)×(22/7)×(6^2) sq.cm

=> (1/6)×(22/7)×(6×6)

=>(1×22×6×6)/(6×7)

=>(22×6)/7

=>(22/7)×6

=>6π sq.cm

or

=>132/7

=> 18.857....

=>18.86 sq.cm(approximately)

Answer:-

Area of the given sector is 6π sq.cm or

18.86 sq.cm (approximately)

Used Formula:-

• Area of a sector = (X°/360°)×πr^2 sq.units

• X°=Angle subtends by an arc at the centre of the circle

• r=radius

• π=22/7