In a circle of radius 7cm ,a square ABCD is inscribed.Find the area of the Circle which is outside the square. plz help
Answers
Step-by-step explanation:
Diagonal of the square =(2×7)cm=14cm=(2×7)cm=14cm
Area of the square =12d2=(12×14×14)cm2=91cm2=12d2=(12×14×14)cm2=91cm2

Area of the circle =(227×7×7)cm2=154cm2=(227×7×7)cm2=154cm2
Required area =(154−91)cm2=63cm2=(154-91)cm2=63cm2
Answer:
55.86 cm^2 or nearly 56 cm^2
Step-by-step explanation:
We know,
Area of circle = pi × r × r
Area of circle = pi × r × rArea of Square = (1/2) × (Diagonal)^2
So Given:
Radius of circle (r) = 7cm
Since, square is inscribed in the circle then, diagonal of square will be,
Diagonal = 2 ×7 cm = 14 cm
Area of Square (A1) = (1/2) × (Diagonal) ^2
= (1/2) × (14)^2
A1 = 98 cm^2
Area of Circle (A2) = pi × r × r
= 3.14 × 7 × 7
A2 = 153.86 cm^2
We need to find the area of circle outside the Square. Fo that, we should kbow that, area of circle is greater than the area of square insctibed in circle.
So,
Area of Circle left outside Square,
= A2 - A1
= 153.86 - 98
= 55.86 cm^2
Hence, Area of Circle left outside the Square is found to be 55.86 cm^2 or nearly 56 cm^2
I hope, this will help You.
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