Question

In a circle of radius of 12 cm , a chord subtends an angle of 120 degrees at the centre,find the area of the corresponding minor segment of the circle?​

Answer 1

Answer:

150.72 sq cm

Step-by-step explanation:

area of minor segment

$\frac{x}{360} \times \pi \times {r}^{2} \\ = \frac{120}{360} \times \frac{22}{7} \times 12 \times 12 \\ = \frac{1}{3} \times \frac{22}{7} \times 12 \times 12 \\ = \frac{22}{7} \times 4 \times 12 \\ = 3.14 \times 4 \times 12 \\ = 3.14 \times 48 \\ = 150.72$