Question

In a circle of readius 10cm O is
the centre, OP is perpendicular to AB.If OP=6cm, then
the length of chord AB is​

Answer 1

Answer:

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In a circle of readius 10cm O is

the centre, OP is perpendicular to AB.If OP=6cm, then

the length of chord AB is -

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Given ,

OA=10cm

OC=6cm

∠OCA= 90 ∘

By Pythagoras theorem,

AC =OA^2 −OC^2

=10^2−6^2

AC=8cm

We know that perpendicular from centre of circle bisects the chord

Therefore AB=2AC

$\large\underline\green{\sf AB \: = \: 16\: cm \: .}$

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Answer 2

Answer:

length of cord is 16 cm

Step-by-step explanation:

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