In a circle radius of the circle, AC = 13 units AP perpendicular to BC (BC i s chord). If C= (3,6), P= (7, 9), then the length of AP is
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Answer:
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AP=PB⇒ 'P' is mid pt
AB=2PB
PB
2
+OP
2
=13
2
(In ΔOPB)
OP
2
=
(7−3)
2
+(9−6)
2
=
4
2
+3
2
=5
∴PB
2
=
13
2
−5
2
=12
⇒
AB=24unit
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