in a circle, the length of a chord which is at a distance 15cm from the centre is 16cm then complete the following activity to find the radius of the circle.
please help me!
Answers
Answered by
1
Answer:
Step-by-step explanation:
letchord = AB
distance from ceter=OM
half of AB=AM
chord=16cm
distance from center = 15cm
(distance from center on a chord is it's perpendicular bisector)
so half of chord=8cm
now
in triangle OAM
OA^2 = Om^2 +Am^2
= 15*15+8*8
=289
=√289
=17cm
Answered by
1
Answer:
17cm
Step-by-step explanation:
Letchord = AB
Centre distance = OM
Half AB = AM
Chord = 16cm
Centre distance = 15cm
Chord half = 8cm
Since, In ∆ OAM
OA^2 = OM^2 + AM^2
OA^2 = 15×15+8×8
OA^2 = 225+64
OA^2 = 289
OA = √289
OA = 17cm
I think this may help you
Have a nice day........
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