in a circle the point of intersection of the perpendicular bisectors of two non parallel chords is the center of the circle
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The prove that the perpendicular bisector of two non parallel chords of a circle intersect at its centre. So, by side-side-side, ΔOPR ≅ ΔOQR. Hence, OP = OQ, which means they are radii of the circle as they pas.s from the centre O to the corners
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