in a circle there are 100 number of people standing for a war. with first person there is a sword he killed second person and gave it to third person. third person killed fourth and gave to fifth person. then going on killing at last which member will alive?
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Answer:This is your answer I hope this helps you Explanation:After a lot of serious Mathematical explanations, I thought I would submit a solution that might work for those who understand visual explanations.1. In round one, number 1 picks up the dagger/sword and kills the person next to him - #2. He proceeds to hand the dagger over to #3 who kills #4 and so on.Thus all even numbers die with #100 being the last one to die and the dagger is with #1 for round II.2. In Round II, #1 starts by bumping off #3. Thus, the numbers that survive correspond to (1+4n) and therefore, the last one surviving the round is (1+4*24) ie 97 who proceeds to bump off #99 and hands the dagger to #1.So far so good?3. In Round III, #1 bumps off #5 and hands the dagger to #9. Survivors follow the pattern (1+8n) with #97 being the last one in the round (1+8*12). The person next to him is #1 and it is his turn to get bumped off. Next round starts with #94. In Round IV, survivors are {1+8*(2n+1)} - starting with #9 who bumps off #17 (1+8*2) and hands the dagger to #25 (1+8*3). The last survivor of this round is (1+8*11) #89 who kills #97 and hands the dagger to #9.5. In Round V, survivors are #9 {(1+8*1)}, #25 {(1+8*3)}, #41, #57 & #73. Alternate knocks and #9 kills #25, dagger to #41 who kills #57 who gives dagger to #73 who kills #89 and hands the dagger over to #9.
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