In a circle with center C, the distance of the chord of length 120 cm is 11 cm from C. Find
diameter of the circle.
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Step-by-step explanation:
Given:Let AB be a cord of length120cm and D be point where the line fron centre C meets AB.
CD=11cm
To find:diameter of circle.
Construction:join the points AC or BC.
Proof:
The line from centre of the circle divides the cord into equals halves .
AD=BD=60cm
Consider triangle ADC or BDC and angle D will be 90.
They for right triangle, by applying pathagoras theorem to any one of the triangles (BDC):
BC²=CD²+BD²
BC²=(11)²+(60)²
radius=BC=√121+3600=√3721=61cm.
d=2r=2(61)=122cm.
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