Question

In a circle with center 'O'.AB is a chord and 'M' is its midpoint.Now prove that OM is perpendicular to AB

Answer 1

Step-by-step explanation:

given  AB is chord

also, m is midpoint of AB

∴ AM=BM

construction : join om

proof : as AM = BM

hence we can say that om bisects chord AB

this is only possible when a perpendicular is drawn from the centre of the circle to a chord

∴ om is perpendicular to chord AB

Hence proved.

Answer 2

Answer:

the line drawn from the centre of the circle to bisect the chord is perpendicular to the chord