Question

In a circle with center O and a chord BC, the point D lies on the same side BC as O. If _ BOC = 50° then _ BDC= * ​

Answer 1

Answer:

10000000+100000000=3

Answer 2

∠BDC = 25°

Step-by-step explanation:

Given: ∠BOC=50°

To find: ∠BDC

Concept to be used: the angle subtended by a chord on center is twice the angle subtended by it ion the circle.

Step 1 of 1

In the circle, BC is a chord. O is the center of the circle.

By the theorem - "the angle subtended by a chord on center is twice the angle subtended by it ion the circle".

So, ∠BOC = 2 ∠BDC

$50 =2\angle BDC\\\\\angle BDC=\frac{50}{2} \\\\\angle BDC=25^{o}$

∠BDC = 25°