Question

in a circle with center O and radius 6cm, AB is a chord of length 6cm . Find the area of minor sector AOB.​

Answer 1

Given

AB chord = 6 cm

Radius = 6 cm

To find,

The area of the minor sector AOB.

Solution,

We can easily solve this mathematical problem by using the following mathematical process.

Now, AO and BO are two radius of the circle which mean their lengths will be 6 centimetres.

So, ∆AOB will be an equilateral triangle

Area of ∆AOB = √3/4 × (6)² = √3/4 × 36 = 9√3 cm²

Hence, the area of the minor sector AOB will be 9√3 cm².

Answer 2

Answer:

$18.85cm {}^{2}$

Step-by-step explanation:

OA=OB (radius)

therefore AOB is a equilateral triangle. (6cm)

Angle AOB = 60° ( equilateral triangle)

area of sector = thetha/360° × πrsq.

= 60°/360° × 22/7 × 6 × 6

= 132/7

= 18.85 cmsq