Question

in a circle with center o arc ab is twice of arc bc and angle aob 108 find angle boc

Answer 1

see an circle makes an angle of 360 ° ...
the given date is that the circle is divided into 2 arcs if one angle is 108 degrees the the other will be 360 - 108= 252°

Answer 2

∠BOC = 54°

Step-by-step explanation:

∠AOB = 108°

Arc length AB  = (∠AOB/360°) * 2 π * Radius

Arc length BC  = (∠BOC/360°) * 2 π * Radius

length of arc AB is twice the length of arc BC

=>  (∠AOB/360°) * 2 π * Radius = 2 * (∠BOC/360°) * 2 π * Radius

=> ∠BOC = ∠AOB/2

=> ∠BOC = 108°/2

=> ∠BOC = 54°

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