In a circle with center O, OM
⊥
AB, OM = 3, AM = 4, find OA.
Answers
Answered by
5
Answer:
OA is 7
I hope it will help you
Answered by
5
Given :- In a circle with center O, OM ⊥ AB, OM = 3, AM = 4, find OA.
Answer :-
In right angled ∆OMA , we have,
→ OM² + AM² = OA² (By pythagoras theorem)
→ 3² + 4² = OA²
→ 9 + 16 = OA²
→ 25 = OA²
→ 5² = OA²
→ OA = 5 (Ans.)
Learn more :-
PQ and XY are two chords of a circle such that PQ = 6 cm and XY = 12 cm and PQ||XY. If the distance between the chords i...
https://brainly.in/question/24793483
PQRS is a cyclic quadrilateral with PQ = 11 RS = 19. M and N are points on PQ and RS respectively such that PM = 6, SN =...
https://brainly.in/question/27593946
Attachments:
Similar questions