Question

In a circle with center O seg OP perpendicular chord AB, AB = 48 cm OP = 7 cm then find radius of the circle​

Answer 1

Answer:

Therefore,

PR=QR=8cm

RB=4cm

Let, radius OA=OB=r

  OB=OR+RB

=>r=OR+4

=>OR=r−4 

$now \\ \\ op^{2} = or^{2} + pr ^{2} \\ \\ =>r^{2} = (r - 4)^{2} + 8 ^{2} \\ \:=r^{2} = r^{2} - 8^{r} + 16 + 64 \\=> \: 8 ^{r} = 80 \\ => \: r = 10m</p><p></p><p></p><p> \\ =>r=10cm</p><p></p><p>$