Question

In a circle with center seg OP chord AB, AB= 48 cm, OP = 7 cm then find radius of the circle. ​

Answer 1

Step-by-step explanation:

AB=48 cm is a chord of the circle with centre P and radius=r=25 cm.

PN is the perpendicular distance of AB from P.

We know that a chord of a circle is bisected by the line which is the perpendicular distance of the chord from the centre of the given circle.

Therefore, AN=BN=

2

48

cm =24 cm.

Now, in ΔPAN, ∠PNA is a right angle.

ΔPAN is a right one with hypotenuse as PA.

Therefore, Applying Pythagoras theorem, we get PN=

PA

2

−AN

2

=

25

2

−24

2

cm=7cm.

pls mark my answer as brainlist