In a circle with centre 0 and radius 5 cm, AB is a chord of length 5 cm. Find the area of the sector AOB. (Take n = 3.14)
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Answer:
=13.08cm^2
Step-by-step explanation:
in the above information radius and chord are equal
so it forms an equilateral triangle
so the angle made by the chord at the centre is 60
so sector area = (60/360)*3.14*5*5
= (1/6)*(3.14)*25
=13.08cm^2
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