Question

in a circle with centre c take a point p and q on the circle such that pq = radius of the circle join cp and cq .measure,,<pcq.pcq an equiangular triangle?​

Answer 1

Here's Ur Answer:

In OPSQ

∠0+∠P+∠S+∠Q=360

∘

⇒∠O+90  +20  +90  =360

∘

⇒∠O=160

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Angle subtended by PQ at center is twice

that of subtended at circumference

⇒∠O=2∠PMQ

⇒160

∘

=2∠PMQ

⇒∠PMQ=80

∘

In PMQR, Sum of opposite angles =180

∘

 (PMQR is cyclic)

⇒∠M+∠R=180

∘

⇒80

+∠R=180  

⇒∠R=100

∘Stay Cool

Answer 2

Answer:

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