Question

In a circle with centre O,a diameter AB is produced to point P lying outside the circle and PT is tangent to the circle at the point C. If AngleBPT=36degree then angle BCP=?

Answer 1

Step-by-step explanation:

from the smallest number of 4digit which is divisible by 6,8,9

Answer 2

Step-by-step explanation:

Angle COP= 90-36 [Since, angle OCP is 90 as it is the angle formed by tangent and radius.]