in a circle with centre o ab and cd are two diameters perpendicular to each other the length of chord ac is ?
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Let us take OD as x.
Then the value of AC will be:
(AC)²=(AO)²+(OC)²
Moreover OD=OC=AO=OB= radius.
Therefore,
(AC)²= 2x²
AC= √2 x.
Then the value of AC will be:
(AC)²=(AO)²+(OC)²
Moreover OD=OC=AO=OB= radius.
Therefore,
(AC)²= 2x²
AC= √2 x.
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