Question

In a circle with centre 'O' AC is a tangent at A . If OC=4cm and angleAC=30 then the radius of the circle is​

Answer 1

Answer:

∠OAC=90°(∵Radius⊥Tangent)

Therefore,

By exterior angle property,

∠BOC=∠OAC+∠ACO

⇒∠ACO=130°−90°=40°