Question

In a circle with centre O diameter CD are given prove that AD =Bc​

Answer 1

Answer:Here AD and BC are going to act as chords

here o is the centre of the circle and as we know that when the chords will be intersecting each other Vertically opposite angles are going to need formed and and the arcs AD and BC are going to be equal to the measure of angles AOD and measure angle BOC

Hence now we know that chords corresponding to congruent arcs are going

Step-by-step explanation:

Answer 2

Step-by-step explanation:

CF=CG

`/_CFE and /_CGE`

`angleCFE=angleCGE=90^o`

CE=CF

CF=CG

`/_CFEcong/_CGE`

so,FE=EG

Similarly,AF=DG

AF+FE=DG+GT

AE=DE

so,EB=EC

`/_AEC and /_DEB` is similar

`(AC)/(BD)=(AE)/(DE)=(CE)/(BE)=1`

So, AC=BD