Question

in a circle with Centre O is drawn and angle BAC=50°find x​

Answer 1

45..........................

Answer 2

The value of x is 40°.

Step-by-step explanation:

Given information: O is center of circle, ∠BAC=50°.

According to central angle theorem, the central angle subtended by two points A and B on circle O is twice the inscribed angle subtended by A and B.

Using central angle theorem, we get

$\angle BOC=2\times \angle BAC$

$\angle BOC=2\times (50)$

$\angle BOC=100$

OB and OC are radius of the circle. So, OB=OC and OBC is a isosceles triangle.

$\angle OBC=\angle OCB=x$

The sum of interior angles of a triangle is 180.

$\angle OBC+\angle OCB+\angle BOC=180$

$x+x+100=180$

$2x=80$

$x=40$

Therefore, the value of x is 40°.

#Learn more

In the figure,O is the centre of the circle.angle AOB=100° find angle ADB​.

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