In a circle with centre O, OM is drawn perpendicular to the chord
AB. If AB = 6 cm and OM = 4 cm find the measure of the radius
of the circle.
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Given :
AB ( Chord ) = 6 cm
OM ( Perpendicular ) = 4 cm
To Find :
The Radius of the Circle
Procedure :
Construction : Join AO
Given, OM is perpendicular to AB
→ AM = MB = 1/ 2 × AB
= 1/2 × 6
= 3 cm ( i.e AM = MB = 3 cm )
From ∆ AMO ( By Pythagoras Theorem )
AO² = AM² + OM²
AO ² = 3 ² + 4²
AO ² = 9 + 16
AO ² = 25
AO = √25
AO = 5 cm
Radius of the Circle is 5 cm
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