In a circle with centre O, PQ and XY are chords. If
Z POQ = 120°, Z OXY = 30° and XY = 8 cm, then find PQ.
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XY = PQ = 8cm
In Circle O,
In Triangle POQ,
Ang. POQ = 120°,
Triangle POQ is an isoceles triangle (This is Property of Circles; OP, OQ are Radius inside a cirle),
Using the Sum of Angles of a Triangle, Angle OPQ = OQP = 30°
Triangle OXY,
This triangle is also an isoceles Triangle
Angle OXY = OYX = 30°
Therefore Angle XOY = 120°
Taking into consideration
Angle OXY = OPQ = 30°
Angle OYX = OQP = 30°
Angle POQ = XOY = 120°
OP = OQ = OX = OY (Radius of Circle)
Therefore, Triangle OXY and Triangle OPQ are Congruent.
So, XY = PQ = 8cm.
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