Question

In a circle with Centre O PQ is the diameter of the circle and QR is a tangent if angle QOS is equal to 70 degrees find angle PRQ​

Answer 1

Answer:

given= QOS=70°

FIND= QRP=?

QS arc subtends QPS

so, QPS=1/2 x QOS = 1/2 x 70 = 35°

QPS = 35°

PQR+PRQ+RPQ= 180

90+35+PRQ=180

PRQ = 180-125

PRQ = 55°