In a circle with centre o radius, is 34 cm, l (OM) =30 cm then find l (AB).
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Answer:32cm
Explanation:
since we know that AM and BM are equal
(PERPENDICULAR FROM THE CENTRE BISECTS THE CHORD)
and given,
OM=30 cm
OB=34 cm (since it's radius of circle)
By Pythagorean formula,
OM^2+BM^2=OB^2
30^2+MB^2=34^2
MB^2=1156-900
=256
MB=16 cm
AB=MB+AM
=2MB
=2×16=32cm
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