Question

In a circle with centre O,see Pq is chord of length 8. OA is perpendicular chord PQ then find AP
​

Answer 1

Answer:

AP =4cm

Step-by-step explanation:

Given :

Length of chord = 8cm

OA perpendicular to PQ

Then PQ= PA + AQ

We know that perpendiculars bisect the chord

therefore

PQ = 2 AP

8= 2 AP

8/2 =AP

AP =4 cm

Hope it helps you

Mark as brainliest answer