In a circle with centre O, segment PQ is a chord of length 18 cm, segment OA
perpendicular to chord PQ, find length AQ, and segment AO, segment QO is equal
to 15 cm.
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Answer:
Since OA is perpendicular to PQ
Then OA bisects PQ
Therefore AQ=½PQ=½*18=9cm
Also triangle OAQ is right angle triangle.
By Pythagoras theorem
OQ²=OA²+AQ²
=>OA²=OQ²-AQ²
=15²-9²=225-81=144
=>OA=12
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