In a circle with centre O, segment PQ is a chord of length 18 cm, segment OA
perpendicular to chord PQ, find length AQ, and segment AO, segment QO is equal
to 15 cm.
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Step-by-step explanation:
AP=AQ,BP=PR and CR=CQ
Perimeter of ∆ABC=AB+BR+RC+CA
=AB+BP+CQ+CA
=AP+AQ
=2AP
∆APO is right angled triangle AO²=AP²+PO²
13²=Ap²+5²
AP²=144
AP=12
Perimeter of ∆ABC=24cm
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