Question

In a circle with centre P, AB is a chord and PA = 4 cm. In a circle with centre Q, XY is a chord and QX= 4 cm. If angle APB = 80°, angle QXY = 50° and AB = 5 cm, then find XY.​

Answer 1

Step-by-step explanation:

Here, radius of the circle = 4 cm

Length of the chord = 4 cm

So, the triangle formed by the cord and two radius is an equilateral triangle of side 4 cm.

We know that in an equilateral triangle each angle measures 60o

So, area of sector =πr2×θ360o

=227×42×60360

=8.38 cm2

Answer 2

The ans of this problem is 6cm